If you are a Visible Mobile customer and would rather not build your own group, we'd like to invite you to join our stable 900+ member party to save $180/year and pay just $25/month now by visiting https://www.visible.com/p/Ollanketo and select join Party. We accept all new members several times each day and all group members can go to the Party Pay tab in their account and accept any new members requesting to join. Thank you to everyone who has joined us recently and we'd appreciate a Kudo. 👍
Visible Mobile includes unlimited talk, text, and data and is rapidly expanding 5G coverage. Visit https://www.visible.com/deals/ and use code 3p9766 to sign up for the mobile service. Choose the incentive deal that’s best for you including one that offers two months of wireless service for $15.00/month using promo code SUMMER. For an additional initial cash back offer, (currently $20.00) visit https://www.rakuten.com/visible.com. If you have any questions about your phone or their mobile service, click the link to chat with a representative. They are both friendly and knowledgeable. They'll overnight ship you a SIM card for your device. Once you get the SIM card, you can login to your visible account to activate your service and then join our stable party at the above link.
Stay safe and have a great day!
Hello, I want to join your plan, but I want to keep my original mobile phone number and I don’t know how to do. And I want to ask how long it will take me to get the new plan card, because my old plan will expire in two days.
If you opt to keep your own device you can choose a physical SIM card which is overnighted to you through FedEx. You are also able to choose an ESIM if your device support one which can be activated immediately.
The way Party Pay works is that you will join the party after you sign up for Visible.
I will include the best steps and deals (in my personal opinion) to get service started with your current cell number, pay the minimum for your first month, get an accessory (such as Pixel Buds) or a Mastercard gift card with $100-$200 after two or three months of service payments.
Then to make it an even better experience, I will help you join the party after your service is connected so you are able to pay $25/month for the same plan as $40/month!
To start, if you use:
To use at checkout enter code: 3r7JJr
That is my personal referral link and you will be provided one as well. Any time someone uses your referral code to sign up they pay $5 for the first month of service and you are given the next month for only $5!
Make sure to check the current Visible deals to see if any fit what you need. You are able to use most of the deals with the referral code and Party Pay! Currently, my personal favorite is receive a $200 gift card (many options from MasterCard to Amazon) For that deal you need to transfer your current phone number to Visible and make three full monthly payments to get the gift card.
Once you decide which deal works best for you all that is needed is to follow the prompts to place your order. When you receive your new SIM or eSIM you will activate your new service which is very quick through the Visible app and you are almost set to go!
The last step is to follow the link from the original post and request to join the party! Once you are accepted your monthly payment is dropped to an amazing $25 per month!
I hope that helped! I would be happy to answer anything I am able to if you need anything else.
Hello Warren - I tried to purchase a sim card and service using your code 3r7JJr, which was 'applied" on the order screen, and the price came as $40 for "first month total".
Is that code still good ?
I just saw your reply to a previous post that you joined our party and were still charged $40. That is the first time I've ever heard of that. Please DM me if you never got that fixed and make sure you click through the link to get your monthly service reduced to $25/month every month.
Yes, that’s the problem. As soon as you activate your SIM card, you’ll be able to join. Please DM me if you have any More questions.